For this case we have the following function:
[tex]f (x) = (3x + 5) (x ^ 2-6x + 9) ^ 2[/tex]
To find the roots we must equal the function to 0, that is:
[tex](3x + 5) (x ^ 2-6x + 9) ^ 2 = 0[/tex]
So:
[tex]3x + 5 = 0[/tex]
Subtracting 5 from both sides:
[tex]3x = -5[/tex]
Dividing between 3 on both sides:
[tex]x = - \frac {5} {3}[/tex]
Thus, one of the roots is [tex]x = - \frac {5} {3}[/tex]
Answer:
True
