Respuesta :

Answer:

all work is answer and shown and pictured

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Answer:

The domain is:   {x > -5 and x≠0 }

Step-by-step explanation:

We are given a function f(x) and g(x) as follows:

[tex]f(x)=\dfrac{1}{x}[/tex]

and

[tex]g(x)=\sqrt{x+5}[/tex]

Now, the function (f/g)(x) is given by:

[tex](\dfrac{f}{g})(x)=\dfrac{f(x)}{g(x)}[/tex]

This means that:

[tex](\dfrac{f}{g})(x)=\dfrac{\dfrac{1}{x}}{\sqrt{x+5}}[/tex]

i.e.

[tex](\dfrac{f}{g})(x)=\dfrac{1}{x\sqrt{x+5}}[/tex]

Now we know that a square root function is defined if the radicand is positive.

i.e.

Here,

x+5 ≥ 0

i.e.

x ≥ -5

Also,

x≠0 and √(x+5)≠0

( otherwise the denominator will be zero and hence the expression will be not defined)

Hence, we have:

x≠0 and x≠ -5

This means that:

 x > -5 and x≠0

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