Respuesta :
Answer:
The domain is: {x > -5 and x≠0 }
Step-by-step explanation:
We are given a function f(x) and g(x) as follows:
[tex]f(x)=\dfrac{1}{x}[/tex]
and
[tex]g(x)=\sqrt{x+5}[/tex]
Now, the function (f/g)(x) is given by:
[tex](\dfrac{f}{g})(x)=\dfrac{f(x)}{g(x)}[/tex]
This means that:
[tex](\dfrac{f}{g})(x)=\dfrac{\dfrac{1}{x}}{\sqrt{x+5}}[/tex]
i.e.
[tex](\dfrac{f}{g})(x)=\dfrac{1}{x\sqrt{x+5}}[/tex]
Now we know that a square root function is defined if the radicand is positive.
i.e.
Here,
x+5 ≥ 0
i.e.
x ≥ -5
Also,
x≠0 and √(x+5)≠0
( otherwise the denominator will be zero and hence the expression will be not defined)
Hence, we have:
x≠0 and x≠ -5
This means that:
x > -5 and x≠0