Respuesta :
Answer:
Here is code in c++.
#include <bits/stdc++.h>
using namespace std;
int main() {
//declare array of size 5x5
int arr[5][5];
// variables to store row sum and column sum
int row_sum=0,col_sum=0;
cout<<"please enter the elements of the array: "<<endl;
//reading elements of the array
for(int i=0;i<5;i++)
{
for(int j=0;j<5;j++)
{
cin>>arr[i][j];
}
cout<<endl;
}
cout<<"\nsum of each row:"<<endl;
for(int i=0;i<5;i++)
{
row_sum=0;
for(int j=0;j<5;j++)
{
//calculating sum of each row
row_sum=row_sum+arr[i][j];
}
//printing the sum of each row
cout<<"sum of row "<<i+1<<" is :"<<row_sum<<endl;
}
cout<<"sum of each column :"<<endl;
for(int i=0;i<5;i++)
{
col_sum=0;
for(int j=0;j<5;j++)
{
//calculating sum of each column
col_sum=col_sum+arr[j][i];
}
//printing the sum of each column
cout<<"sum of column "<<i+1<<" is :"<<col_sum<<endl;
}
return 0;
}
Explanation:
Declare an array of integer type of size 5x5 to store the element from the user. Read the elements from the user.First travers the array row by row and find the sum of each row and print them.After that travers the array column by column and find the sum of each column and print them.
Output:
please enter the elements of the array:
23 43 55 23 78 52 64 88 43 56 23 56 343 76 61 59 34 67 90 98 99 12 3 7 123
sum of each row:
sum of row 1 is :222
sum of row 2 is :303
sum of row 3 is :559
sum of row 4 is :348
sum of row 5 is :244
sum of each column :
sum of column 1 is :256
sum of column 2 is :209
sum of column 3 is :556
sum of column 4 is :239
sum of column 5 is :416
