Question

A bar with a length of L moves through a 0.25 T magnetic field at a speed of v. What is the magnitude of the emf across the bar? The motion is perpendicular to the field direction.

Answer 1

Answer:

0.25 v L

Explanation:

length of the bar = L

magnetic field, B = 0.25 T

Speed of bar = v

The formula for the motional emf is given by

e = B x v x L x Sinθ

Where, e be the induced emf, v be the speed, L be the length of the conductor, θ be the angle between the velocity vector and the length vector

Here, θ = 90 degree

So, e = B x v x L

e = 0.25 x v x L

e = 0.25 v L