Define the points ​P(negative 4−4​,negative 2−2​) and ​Q(33​,negative 4−4​). Carry out the following calculation. Find two vectors parallel to ModifyingAbove QP with right arrowQP with length 22.

Respuesta :

Answer:

The required vectors are [tex]u=<-\frac{14}{\sqrt{53}},\frac{4}{\sqrt{53}}>[/tex] and [tex]v=<\frac{14}{\sqrt{53}},-\frac{4}{\sqrt{53}}>[/tex].

Step-by-step explanation:

Given information: P(-4,-2) and Q(3,-4).

We need to find the two vectors parallel to [tex]\overrightarrow {QP}[/tex] with length 2.

If [tex]A(x_1,y_1)[/tex] and [tex]B(x_2,y_2)[/tex], then

[tex]\overrightarrow {AB}=<x_2-x_1,y_2-y_1>[/tex]

[tex]|\overrightarrow {AB}|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the above formula we get

vector QP is,

[tex]\overrightarrow {QP}=<-4-3,-2-(-4)>=<-7,2>[/tex]

Magnitude of vertor QP is,

[tex]|\overrightarrow {QP}|=\sqrt{(-4-3)^2+(-2-(-4))^2}[/tex]

[tex]|\overrightarrow {QP}|=\sqrt{(-7)^2+(2)^2}[/tex]

[tex]|\overrightarrow {QP}|=\sqrt{49+4}[/tex]

[tex]|\overrightarrow {QP}|=\sqrt{53}[/tex]

Using vector is

[tex]\widehat {QP}=\frac{\overline {QP}}{|\overline {QP}|}[/tex]

[tex]\widehat {QP}=\frac{1}{\sqrt{53}}<-7,2>[/tex]

[tex]w=\widehat {QP}=\frac{1}{\sqrt{53}}<-\frac{7}{\sqrt{53}},\frac{2}{\sqrt{53}}>[/tex]

Multiply vector w by 2 to get a parallel vector parallel of QP in same direction.

[tex]u=2w=<-\frac{14}{\sqrt{53}},\frac{4}{\sqrt{53}}>[/tex]

Multiply vector w by -2 to get a parallel vector parallel of QP in opposite direction.

[tex]v=-2w=<\frac{14}{\sqrt{53}},-\frac{4}{\sqrt{53}}>[/tex]

Therefore the required vectors are [tex]u=<-\frac{14}{\sqrt{53}},\frac{4}{\sqrt{53}}>[/tex] and [tex]v=<\frac{14}{\sqrt{53}},-\frac{4}{\sqrt{53}}>[/tex].

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