Question

Determine the number of moles of the compound and determine the number of moles of each type of atom in each of the following.a. 25.0 g of propylene, C3H6b. 3.06 x 10^-3g of the amino acid glycine, C2H5NO2c. 25 lb of the herbicide Treflan, C13H16N2O4F (1lb = 454 g)d. 0.125 kg of the insecticide Paris Green, Cu4(AsO3)2(Ch3CO2)2e. 325 mg of aspirin, C6H4(CO2H)(CO2CH3)

Answer 1

Explanation:

$n=\frac{\text{Mass of compound}}{\text{Molar mass of compound}}$

n = number of moles

a. Mass of propylene = 25 g

Molar mass of propylene =42 g/mol

Moles of polypropyne:

$\frac{25 g}{42 g/mol}=0.5952 mol$

In 1 mol there are 3 moles of carbon atoms, then in 0.5952 moles of propyene:

$3\times 0.5952 mol=1.7856 mol$ of carbon

In 1 mol there are 6 moles of hydrogen atoms, then in 0.5952 moles of propyene:

$6\times 0.5952 mol=3.5712 mol$ of hydrogen

b. Mass of amino acid = $3.06\times 10^{-3} g$

Molar mass of amino acid: 75 g/mol

Moles of amino acid:

$\frac{3.06\times 10^{-3} g}{75 g/mol}=0.0000408 mol$

In 1 mol there are 2 moles of carbon atoms, then in 0.0000408 moles of amino acid :

$2\times 0.0000408 mol=0.0000816 mol$ of carbon atom

In 1 mol there are 6 moles of hydrogen atoms, then in 0.0000408 moles of amino acid :

$5\times 0.0000408 mol=0.000204 mol$ of hydrogen atom

In 1 mol there are 2 moles of oxygen atoms, then in 0.0000408 moles of amino acid :

$2\times 0.0000408 mol=0.0000816 mol$ of oxygen atom

In 1 mol there are 1 moles of nitrogen atoms, then in 0.0000408 moles of amino acid :

$1\times 0.0000408 mol=0.0000408  mol$ of nitrogen

c. Mass of herbicide Treflan = 25 lb = 11350 g

1 lb = 454 g

Molar mass of herbicide Treflan = 283 g/mol

Moles of herbicide Treflan = $\frac{11350 g}{283 g/mol}=40.1060 mol$

In 1 mol there are 13 moles of carbon atoms, then in 40.1060 moles of amino acid :

$13\times 40.1060 mol=521.37 mol$ of carbon atom

In 1 mol there are 16 moles of hydrogen atoms, then in 40.1060 moles of amino acid :

$16\times 40.1060 mol=641.696 mol$ of hydrogen atom

In 1 mol there are 4 moles of oxygen atoms, then in 40.1060 moles of amino acid :

$4\times 40.1060 mol=160.424 mol$ of oxygen atom

In 1 mol there are 2 moles of nitrogen atoms, then in 40.1060  moles of amino acid :

$2\times 40.1060 mol=80.212 mol$ of nitrogen atom

In 1 mol there are 1 moles of fluorine atoms, then in 40.1060 moles of amino acid :

$1\times 40.1060 mol=40.1060 mol$ of fluorine

d. Mass of insecticide Paris Green = 0.125 kg = 125 g

1000 g = 1 kg

Molar mass of insecticide Paris Green = 1,013.79 g/mol

Moles of insecticide Paris Green:

$\frac{125 g}{1,013.79 g/mol}=0.1233 mol$

In 1 mol there are 4 moles of carbon atoms, then in 40.1060 moles of insecticide Paris Green :

$4\times 0.1233 mol=0.4932 mol$ of carbon atom

In 1 mol there are 6 moles of hydrogen atoms, then in 40.1060 moles of insecticide Paris Green :

$6\times 0.1233 mol=0.7398 mol$ of hydrogen atom

In 1 mol there are 10 moles of oxygen atoms, then in 40.1060 moles of insecticide Paris Green:

$10\times 0.1233mol=1.233 mol$ of oxygen atom

In 1 mol there are 4 moles of copper atoms, then in 40.1060  moles of insecticide Paris Green:

$4\times 0.1233 mol=0.4932 mol$ of nitrogen atom

In 1 mol there are 2 moles of arsenic atoms, then in 40.1060 moles of insecticide Paris Green :

$2\times 0.1233mol=0.2466 mol$ of fluorine

e. Mass of aspirin = 325 mg = 0.325 g

1 g = 1000 mg

Molar mas of aspirin = 180 g/mol

Moles of aspirin:

$\frac{0.325 g}{180 g}=0.001805 mol$

In 1 mol there are 9 moles of carbon atoms, then in 0.001805 moles of aspirin :

$2\times 0.001805 mol=0.003611 mol$ of carbon atom

In 1 mol there are 8 moles of hydrogen atoms, then in 0.001805 moles of aspirin:

$8\times 0.001805 mol=0.01444 mol$ of hydrogen atom

In 1 mol there are 4 moles of oxygen atoms, then in 0.001805 moles of aspirin:

$4\times 0.001805 mol=0.007222 mol$ of oxygen atom