Answer:
[tex]9.50\times 10^{-1}\ kg=950\ g[/tex]
Step-by-step explanation:
Given : Expression [tex]9.50\times 10^{-1}\ kg[/tex]
To find : Write expression converted to the basic unit (with no prefix) and expressed in standard exponential notation to the proper number of significant digits ?
Solution :
The basic unit of kg is to convert into gram.
We know, 1 kg=1000 g
So, [tex]9.50\times 10^{-1}\ kg=9.50\times 10^{-1}\times 1000\ g[/tex]
[tex]9.50\times 10^{-1}\ kg=9.50\times 10^{2}\ g[/tex]
Now, Convert standard exponential notation to the proper number of significant digits,
[tex]9.50\times 10^{-1}\ kg=\frac{950}{100}\times 100\ g[/tex]
[tex]9.50\times 10^{-1}\ kg=950\ g[/tex]
Therefore, [tex]9.50\times 10^{-1}\ kg=950\ g[/tex]