Question

Let f(x) = 1 / x and g(x) = x ^ 2 - 2. What is (f g)(-3) )?

Answer 1

Answer:

$f(g(-3))=1/7$

Step-by-step explanation:

we have

$f(x)=\frac{1}{x}$

$g(x)=x^{2} -2$

we know that

$(fg)(x)=f(g(x))=\frac{1}{x^{2} -2}$

For x=-3

substitute

$f(g(-3))=\frac{1}{(-3)^{2} -2}=1/7$

therefore

$f(g(-3))=1/7$