Answer : The mass of oxygen gas produced will be 4.45 grams
Explanation : Given,
Mass of water = 5.2 g
Molar mass of water = 18 g/mole
Molar mass of [tex]O_2[/tex] = 32 g/mole
The balanced chemical reaction will be,
[tex]6CO_2+6H_2O\overset{sunlight}\rightarrow C_6H_{12}O_6+6O_2[/tex]
First we have to calculate the moles of water.
[tex]\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}[/tex]
[tex]\text{Moles of }H_2O=\frac{2.5g}{18g/mole}=0.139mole[/tex]
Now we have to calculate the moles of oxygen.
From the balanced chemical reaction, we conclude that
As, 6 moles of water react to give 6 moles of oxygen gas
So, 0.139 moles of water react to give 0.139 moles of oxygen gas
Now we have to calculate the mass of oxygen gas.
[tex]\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2[/tex]
[tex]\text{Mass of }O_2=0.139mole\times 32g/mole=4.45g[/tex]
Therefore, the mass of oxygen gas produced will be 4.45 grams