Respuesta :
Answer : The identity of the metal is, iron (Fe).
Explanation :
As we are given that:
65.57 % Cl by mass means that 65.57 gram of chlorine present in 100 grams of compound.
Mass of compound = 100 g
Mass of chlorine = 65.57 g
Mass of metal = 100 - 65.57 = 34.43 g
First we have to calculate the moles of chlorine.
[tex]\text{Moles of }Cl=\frac{\text{Mass of }Cl}{\text{Molar mass of }Cl}=\frac{65.57g}{35.5g/mole}=1.847mole[/tex]
The given formula of compound is, [tex]MCl_3[/tex]
The ratio of M : Cl = 1 : 3
Now we have to calculate the moles of metal.
As, 3 moles of Cl combine with 1 mole of metal
So, 1.847 mole of Cl combine with [tex]\frac{1.847}{3}=0.6157[/tex] mole of metal
Now we have to calculate the molar mass of metal.
[tex]\text{Molar mass of metal}=\frac{\text{Given mass of metal}}{\text{Moles of metal}}=\frac{34.43g}{0.6157mole}=55.92g/mole[/tex]
The molar mass of metal is 55.92 g/mole. From this we conclude that the metal is iron (Fe). So, the formula will be, [tex]FeCl_3[/tex]
Hence, the identity of the metal is, iron (Fe).
Answer: The metal is iron.
Explanation:
To calculate the mass percent of element in a given compound, we use the formula:-
[tex]\text{Mass percent of chlorine}=\frac{\text{Mass of chlorine}}{\text{Molar mass of}MCl_3\times 100[/tex]
Mass of [tex]MCl_3=1\times x+3\times 35.5=x+106.5g/mol[/tex]
Mass of chlorine = [tex]3\times 35.5=106.5g/mol[/tex]
[tex]\text{Mass percent of chlorine}=\frac{106.5}{x+106.5}\times 100[/tex]
Given : [tex]\text{Mass percent of chlorine}=65.57\%[/tex]
Equating the two equations :
[tex]\frac{106.5}{x+106.5}\times 100=65.57\%[/tex]
[tex]x=56g/mol[/tex]
Thus the atomic mass of metal is 56g/mol and the element is iron.
