Respuesta :
Answer:
[tex]x_{1} =-6\\x_{2} =1[/tex]
Step-by-step explanation:
The given equation is
[tex](x+2)(x+3)=12[/tex]
First, we need to apply distributive property to have the quadratic expression
[tex]x^{2} +3x+2x+6=12\\x^{2} +5x+6-12=0\\x^{2} +5x-6=0[/tex]
We need to find two numbers which product is -6 and which difference is 5. Those numbers are 6 and 1, because 6 - 1 = 5, and 6(-1) = -6.
[tex]x^{2} +5x-6=(x+6)(x-1)=0[/tex]
If we apply the zero product property, that means each binomial is equal to zero
[tex]x+6=0\\x-1=0[/tex]
Therefore, the solutions are
[tex]x_{1} =-6\\x_{2} =1[/tex]