Answer:
(2y+1)(4y+3a)
Step-by-step explanation:
The given expresion is:
[tex]8 {y}^{2} + 4y - 6ay - 3a[/tex]
We need to factor by grouping.
[tex]4y(2y + 1) - 3a(2y + 1)[/tex]
[tex](2y + 1)(4y - 3a)[/tex]
Now we cannot factorize further.
Therefore the complete factorization of the given expresion is (2y+1)(4y-3a)
