Question

A restaurant’s dining room measures 30 ft by 40 ft. If the fire code requires one square meter per guest, what is the seating capacity?

Answer 1

The restaurant is 30*40= 1200 square feet

1 square meter is 10.76 sq feet

1200/10.76 ~=111.5

Assuming people are integers, the restaurant has a max seating capacity of 111

Answer 2

Answer:

111 guest

Step-by-step explanation:

It is given that a restaurant’s dining room measures 30 ft by 40 ft.

Area of a rectangle is

$Area=length\times width$

Area of the restaurant’s dining room floor is

$Area=30\times 40$

$Area=1200$

The area of the floor is 1200 square feet.

It is given that the fire code requires one square meter per guest.

We know that

1 square ft  = 0.092903 square meter

1200 square ft  = 1200 × 0.092903 square meter

1200 square ft  = 111.4836 square meter

The number of guests can not be a fraction values. So approx the value to the preceding integer.

$111.4836\approx 111$

Therefore, the seating capacity of restaurant is 111.