Answer:
Bandwidth of the Band Pass Filter, BW = 88 - 5 = 83 kHz
center frequency, f = 20.976 kHz
Given:
Upper cut off frequency, [tex]f_{c1}[/tex] = 88 kHz
Lower cut off frequency, [tex]f_{c1}[/tex] = 5 kHz
Solution:
Bandwidth of the Band Pass Filter is the difference between its upper cut-off frequency and its lower cut-off frequency and thus is given by:
Bandwidth, BW = [tex]f_{c1}[/tex] - [tex]f_{c1}[/tex]
Bandwidth of the Band Pass Filter, BW = 88 - 5 = 83 kHz
Now, to calculate its center frequency, f:
f = [tex]\sqrt{f_{c1}\times f_{c2}}[/tex]
f = [tex]\sqrt{88\times 10^{3}\times 5\times 10^{3}}[/tex]
f = 20.976 kHz
