Answer:
[tex]\dfrac{1}{231}[/tex]
Step-by-step explanation:
The product of all the fractions in the Set k is
[tex]\dfrac{1}{1+2} \cdot \dfrac{2}{2+2}\cdot\dfrac{3}{3+2}\cdot \dfrac{4}{4+2} \cdot\cdot\cdot\dfrac{20}{20+2}=\\\\\\\dfrac{1\cdot2\cdot3\cdot4\cdot\cdot\cdot 20}{3\cdot4\cdot5\cdot\cdot\cdot20\cdot21\cdot22}=\dfrac{2}{21\cdot22}=\dfrac{1}{21\cdot11}=\dfrac{1}{231}[/tex]