Find all points having an​ x-coordinate of 3 whose distance from the point left parenthesis negative 1 comma negative 6 right parenthesis is 5.

Respuesta :

Answer:

The required points are (3,-3) and (3,-9)

Step-by-step explanation:

The distance between 2 points [tex](x_{1},y_{1}),(x_{2},y_{2})[/tex] is given by

[tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]

Let all the required points have co-ordinates of (3,y), thus according to the given condition we have

Distance between [tex](3,y),(-1,-6)[/tex] equals 5

Applying values in the above equation we get

[tex]5=\sqrt{(-1-3)^{2}+(-6-y)^{2}}\\\\\Rightarrow 25=16+36+y^{2}+12y\\\\=y^{2}+12y+27=0[/tex]

Solving the quadratic equation in 'y' we get

[tex]y=\frac{-12\pm \sqrt{144-4\times 1\times 27}}{2}\\\\\therefore y=-3\\ y=-9[/tex]  

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