Answer:
The required points are (3,-3) and (3,-9)
Step-by-step explanation:
The distance between 2 points [tex](x_{1},y_{1}),(x_{2},y_{2})[/tex] is given by
[tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]
Let all the required points have co-ordinates of (3,y), thus according to the given condition we have
Distance between [tex](3,y),(-1,-6)[/tex] equals 5
Applying values in the above equation we get
[tex]5=\sqrt{(-1-3)^{2}+(-6-y)^{2}}\\\\\Rightarrow 25=16+36+y^{2}+12y\\\\=y^{2}+12y+27=0[/tex]
Solving the quadratic equation in 'y' we get
[tex]y=\frac{-12\pm \sqrt{144-4\times 1\times 27}}{2}\\\\\therefore y=-3\\ y=-9[/tex]