Respuesta :
[tex]\bf 4x-2y+3=1\implies 4x-2y = -2\implies -2y=-4x-2\implies y=\cfrac{-4x-2}{-2} \\\\\\ y=\cfrac{-4x}{-2}+\cfrac{-2}{-2}\implies y=2x+1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]
Answer:
y = 2x + 1.
Step-by-step explanation:
The slope-intercept equation of a line is in the form:
y = mx + b,
where
- m is the slope of the line, and
- (0, b) is the y-intercept of the line.
The coefficient in front of y is now 2. Reduce this coefficient to 1. Multiply both sides of the equation by 1/2:
2x - y + 3/2 = 1/2.
Separate y from x and the constant. Add y - 1/2 to both sides of this equation:
y = 2x + 1.
This expression satisfies the form y = mx + b:
- m = 2,
- b = 1.