Respuesta :

Answer:

[tex]x_1=e^{18} \quad \text{and} \quad x_2=e^{12}[/tex]

Step-by-step explanation:

We want to solve the equations

[tex]\ln(x_2)=12 \quad \text{and} \quad x_1=e^{6}x_2[/tex]

For the first equation we have

[tex]x_2=e^{12}[/tex]

and so, for the second equation holds

[tex]x_1=e^{6}\cdot e^{12}=e^{6+12}=e^{18}.[/tex]

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