Answer:
[tex]Q=nq=\frac{n}{n+1}\frac{a-c}{b}[/tex]
if n=1 (monopoly) we have [tex]Q^M=\frac{1}{2}\frac{a-c}{b}[/tex]
if n goes to infinity (approaching competitive level), we get the competition quantity that would be [tex]Q^c=\frac{a-c}{b}[/tex]
Explanation:
In the case of a homogeneous-good Cournot model we have that firm i will solve the following profit maximizing problem
[tex]Max_{q_i} \,\, \Pi_i=(a-b(\sum_{i=1}^n q_i)-m)q_i[/tex]
from the FPC we have that
[tex]a-b\sum_{i=1}^n q_i -m -b q_i=0[/tex]
[tex]q_i=\frac{a-b \sum_{i=2}^n q_i-m}{2b}[/tex]
since all firms are homogeneous this means that [tex]q_i=q \forall i[/tex]
then [tex]q=\frac{a-b (n-1) q-m}{2b}=\frac{a-m}{(n+1)b}[/tex]
the industry output is then
[tex]Q=nq=\frac{n}{n+1}\frac{a-c}{b}[/tex]
if n=1 (monopoly) we have [tex]Q^M=\frac{1}{2}\frac{a-c}{b}[/tex]
if n goes to infinity (approaching competitive level), we get the competition quantity that would be [tex]Q^c=\frac{a-c}{b}[/tex]