Question

A fixed amount of an ideal monatomic gas is maintained at constant volume as it is cooled by 50 K. This feat is accomplished by removing 400 J of energy from the gas. How much work is done by the gas during this process

Answer 1

Answer: 0 Joules

Explanation:

According to first law of thermodynamics:

$\Delta E=q+w$

$\Delta E$=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=$-P\Delta V$  {Work is done by the system when the final volume is greater than initial volume and is negative and vice versa}

Given : The volume is constant , i.e. $\Delta V=0$

w = =[tex]-P\times 0=0J/tex]  

Thus no work is done by the gas during this process.