Question

A ladder leaning against a wall makes a 60 degree angle with the ground. The base of the ladder is 4 m from the building. How high above the ground is the top of the ladder?

( THE ANSWER NEEDS TO BE IN REDUCED RADICAL FORM )

Answer 1

In the triangle formed by the ladder, we have

$\tan60^\circ=\dfrac x4$

where $x$ is the height of the top of the ladder. Then

$x=4\tan60^\circ=\boxed{4\sqrt3}$