Zohar is using scissors to cut a rectangle with a length of 5x – 2 and a width of 3x + 1 out of a larger piece of paper. Which expression can be used to find the perimeter of the rectangle and what is the perimeter if x = 4?

Respuesta :

Answer with Step-by-step explanation:

Zohar cut a rectangle with a length of 5x – 2

and a width of 3x + 1

We know that:

Perimeter of rectangle is:

Perimeter=2(length+width)

                =2(5x-2+3x+1)

                =2(8x-1)

                =16x-2

Hence, expression which can be used to find the perimeter of the rectangle is:

16x-2

Now, when x=4

16x-2=16×4-2

        =62

Hence, when x=4 ,Perimeter=62

aachen

Answer:

[tex]P=2(8x-1)[/tex]

[tex]P=62[/tex] at [tex]x=4[/tex]

Step-by-step explanation:

Given: The length of the rectangle is [tex]5x-2[/tex] and width of the rectangle is [tex]3x+1[/tex]

To find: An expression that can be used to find the perimeter of the rectangle, and the perimeter when x is 4.

Solution:

Here, Length is given as [tex]5x-2[/tex]

width of the rectangle is [tex]3x+1[/tex]

Let P represents the perimeter of the rectangle

We know that perimeter of a rectangle is [tex]2(l+w)[/tex]

So, we have

[tex]P=2(l+w)[/tex]

[tex]P=2(5x-2+3x+1)[/tex]

[tex]P=2(8x-1)[/tex]

Therefore, the expression to find the perimeter is [tex]P=2(8x-1)[/tex]

Now, we need to find the perimeter at [tex]x=4[/tex]

On substituting [tex]x=4[/tex]  in [tex]P=2(8x-1)[/tex] we have,

[tex]P=2(8(4)-1)[/tex]

[tex]P=2(32-1)[/tex]

[tex]P=2(31)[/tex]

[tex]P=62[/tex]

Hence, the perimeter is 62 units when x is 4.

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