Respuesta :
Answer with Step-by-step explanation:
Zohar cut a rectangle with a length of 5x – 2
and a width of 3x + 1
We know that:
Perimeter of rectangle is:
Perimeter=2(length+width)
=2(5x-2+3x+1)
=2(8x-1)
=16x-2
Hence, expression which can be used to find the perimeter of the rectangle is:
16x-2
Now, when x=4
16x-2=16×4-2
=62
Hence, when x=4 ,Perimeter=62
Answer:
[tex]P=2(8x-1)[/tex]
[tex]P=62[/tex] at [tex]x=4[/tex]
Step-by-step explanation:
Given: The length of the rectangle is [tex]5x-2[/tex] and width of the rectangle is [tex]3x+1[/tex]
To find: An expression that can be used to find the perimeter of the rectangle, and the perimeter when x is 4.
Solution:
Here, Length is given as [tex]5x-2[/tex]
width of the rectangle is [tex]3x+1[/tex]
Let P represents the perimeter of the rectangle
We know that perimeter of a rectangle is [tex]2(l+w)[/tex]
So, we have
[tex]P=2(l+w)[/tex]
[tex]P=2(5x-2+3x+1)[/tex]
[tex]P=2(8x-1)[/tex]
Therefore, the expression to find the perimeter is [tex]P=2(8x-1)[/tex]
Now, we need to find the perimeter at [tex]x=4[/tex]
On substituting [tex]x=4[/tex] in [tex]P=2(8x-1)[/tex] we have,
[tex]P=2(8(4)-1)[/tex]
[tex]P=2(32-1)[/tex]
[tex]P=2(31)[/tex]
[tex]P=62[/tex]
Hence, the perimeter is 62 units when x is 4.