Question

A bird launches into flight from a point on the ground. The bird can fly 8 feet per second horizontally and 6 feet per second vertically. After 10 seconds, how far has the bird flown relative to its initial spot on the ground?

Answer 1

Answer:

Step-by-step explanation:

Given that a bird launches into flight from a point on the ground. The bird can fly 8 feet per second horizontally and 6 feet per second vertically.

Net speed would be using Pythagorean theorem =$\sqrt{8^2+6^2} =10$

After 10 seconds, it would be 10(10) = 100 feet from its initial spot on the ground.