Question

) The solubility of MnSO4 monohydrate in water at 20 °C is 70.0 g per 100.0 mL of water. A solution at 20 °C that is 4.22 M in MnSO4 monohydrate is best described as a(n) __________ solution. The formula weight of MnSO4 monohydrate is 168.97 g/mol.

Answer 1

Answer:

4.22 M $MnSO_{4}$ monohydrate is best described as supersaturated solution

Explanation:

in a supersaturated solution, solution contains excess amount of solute than its normal capacity.

70.0 g of $MnSO_{4}$ monohydrate = $\frac{70.0}{168.97}$ moles of $MnSO_{4}$ monohydrate

(number of moles is the ratio of mass to molar mass)

So, solubitiy of $MnSO_{4}$ monohydrate in terms of molarity = $\frac{70.0}{168.97}\times \frac{1000}{100}M$ = 4.14 M

As the molarity of given solution in greater than normal solubility of $MnSO_{4}$ monohydrate therefore the solution is best described as a supersaturated solution.