Option: E is the correct answer.
The probability is:
E) 1/32
We know that the outcome on each of the 5 flips are independent of each other.
The probability that the coin will land heads up is 1/2.
The probability that the coin will not land on heads is 1/2.
( Since,
1-(1/2)=1/2 )
Hence, the probability that it will land heads up on the first 3 flips and not on the last 2 flips is:
Head on first×Head on second×Head on third×Tail on fourth×Tail on fifth
[tex]=\dfrac{1}{2}\times \dfrac{1}{2}\times \dfrac{1}{2}\times \dfrac{1}{2}\times \dfrac{1}{2}\\\\=\dfrac{1}{32}[/tex]