Question

calculate the density of mercury if 1.00x10^2g occupies a bolume of 7.36 cm

Answer 1

Answer:

13.6g/cm³

Explanation:

To calculate density of mercury we divide the mass by the volume.

1.00 × 10²g ÷ 7.36cm³ = 13.6g/cm³

Answer 2

Taking into account the definition of density, the density of mercury is 13.59 $\frac{g}{cm^{3} }$.

First you have to know that density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.  This is, density is the relationship that exists between the mass of a substance (or a body) and its volume.

It is an intrinsic property of matter because it does not depend on the amount of substance that is considered.

The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

In this case, you know that:

• mass= 1×10² g
• volume= 7.36 cm³

Replacing in the definition of density:

$density=\frac{1x10^{2}g }{7.36 cm^{3} }$

Solving:

density= 13.59 $\frac{g}{cm^{3} }$

Finally, the density of mercury is 13.59 $\frac{g}{cm^{3} }$.

Learn more about density:

• brainly.com/question/952755?referrer=searchResults
• brainly.com/question/1462554?referrer=searchResults