Certain parts of the world don't have enough fresh drinking water. One possible solution is to tow icebergs from Antarctica and melt them as needed. If 6.10 ✕ 1011 kJ of energy were needed to melt an iceberg, how much did the iceberg weigh? The enthalpy of fusion (melting or freezing) for ice is 6.01 kJ/mol, and 1 metric ton = 1,000 kg. ____ metric tons

Respuesta :

Answer:

Weight of the iceberg is [tex]1.83\times 10^{6}[/tex] metric ton

Explanation:

Molar mass of [tex]H_{2}O[/tex] = 18 g

So, 6.01 kJ of heat energy is needed to melt 18 g of ice

Hence, [tex]6.10\times 10^{11}[/tex] kJ of heat energy is needed to melt [tex]\frac{18\times 6.10\times 10^{11}}{6.01}g[/tex] of ice or [tex]1.83\times 10^{12}[/tex] g of ice

Now, [tex]10^{3}kg[/tex] = 1 metric ton

So, [tex]10^{6}[/tex] g = 1 metric ton   ( 1 kg = 1000 g)

Hence, [tex]1.83\times 10^{12}[/tex] g =[tex]\frac{1\times 1.83\times 10^{12}}{10^{6}}[/tex] metric ton = [tex]1.83\times 10^{6}[/tex] metric ton

So, weight of the iceberg is [tex]1.83\times 10^{6}[/tex] metric ton

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