Answer:
Weight of the iceberg is [tex]1.83\times 10^{6}[/tex] metric ton
Explanation:
Molar mass of [tex]H_{2}O[/tex] = 18 g
So, 6.01 kJ of heat energy is needed to melt 18 g of ice
Hence, [tex]6.10\times 10^{11}[/tex] kJ of heat energy is needed to melt [tex]\frac{18\times 6.10\times 10^{11}}{6.01}g[/tex] of ice or [tex]1.83\times 10^{12}[/tex] g of ice
Now, [tex]10^{3}kg[/tex] = 1 metric ton
So, [tex]10^{6}[/tex] g = 1 metric ton ( 1 kg = 1000 g)
Hence, [tex]1.83\times 10^{12}[/tex] g =[tex]\frac{1\times 1.83\times 10^{12}}{10^{6}}[/tex] metric ton = [tex]1.83\times 10^{6}[/tex] metric ton
So, weight of the iceberg is [tex]1.83\times 10^{6}[/tex] metric ton