Question

What is the fi nal concentration of a 0.6 M NaCl solution if its volume is doubled and the number of moles of solute is tripled?

Answer 1

Answer: The final concentration of solution will be 0.9 M.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n= moles of solute  

$V_s$ = volume of solution in L

Given : molarity = 0.6 i.e. 0.6 moles are present in 1 L of solution.

Given: volume is doubled and moles are tripled

Thus moles = $0.6\times 3=1.8 moles$

volume =$1L\times 2= 2L$

$Molarity=\frac{1.8moles}{2L}=0.9M$

Therefore, the final concentration of solution will be 0.9 M.

Answer 2

The study of chemicals and bonds is called chemistry. When two elements are joined together to form a single compound is called a combination reaction.

The correct answer to the question is 0.9M

What is a mole?

• The mole is the base unit of the amount of substance in the International System of Units (SI).

• It is defined as exactly elementary entities which may be atoms, molecules, ions, or electrons.

What is molarity?

• Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$M= \frac{n}{v}$

The data is given as follow:-

• n= moles of solute  
• Va = volume of solution in L
• Molarity = 0.6 i.e. 0.6 moles are present in 1 L of solution.
• volume is doubled and moles are tripled

The moles are as follows:-

$0.6*3=1.8$.

hence, the molarity is $\frac{1.8}{2} =0.9$

For more information about the question, refer to the link:-

https://brainly.com/question/15209553