Question

A baby sitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.747 m/s2 . What is the velocity of the stroller after it has traveled 6.87 m? Answer in units of m/s.

Answer 1

Answer:

3.2037 m/sec

Explanation:

We have given initial velocity u =0 m/sec

Acceleration $a=0.747m/sec^2$

Distance traveled $s=6.87 m$

We have to find the final velocity v

According to third law of motion $v^2=u^2+2as$

$v^2=u^2+2as=0^2+2\times 0.747\times 6.87=10.2637$

$v=3.2037m/sec$

So the final velocity is 3.2037 m/sec

Answer 2

Answer:

The velocity of the stroller is 3.204 m/s.

Explanation:

Given that,

Distance = 6.87 m

Acceleration = 0.747 m/s²

We need to calculate the velocity

Using equation of motion

$v^2=u^2+2as$

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value into the formula

$v^2=0+2\times0.747\times6.87$

$v^{2}=10.26378$

$v=\sqrt{10.26378}$

$v=3.204\ m/s$

Hence, The velocity of the stroller is 3.204 m/s.