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A girl performs 300 J of work lifting a weight to a height of 2 m. How much
force does she apply? Assume there is no friction.

Respuesta :

r3t40

A lift requires 300J to complete 2m of vertical distance aka height. We must find force exerted by a girl on the object that was lifted 2m vertically.

So we divide.

[tex]F=\dfrac{W}{h}=\dfrac{300\mathrm{J}}{2\mathrm{m}}=150\mathrm{N}[/tex]

Hope this helps.

Answer: The force applied by the girl is 150 N

Explanation:

Work is defined as the force that is causing the movement or displacement of an object.

Mathematically,

[tex]W=F\times d[/tex]

where,

W = work done by the girl = 300 J

F = Force applied by the girl = ?

d = displacement = 2 m

Putting values in above equation, we get:

[tex]300J=F\times 2m\\\\F=\frac{300J}{2m}=150N[/tex]

Hence, the force applied by the girl is 150 N

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