Answer:
The total money invested in the field will be [tex]\$1,623.80[/tex]
Step-by-step explanation:
step 1
Find the dimensions of the field
Let
x -----> the length of the field
y -----> the width of the field
we know that
The perimeter of the field is equal to
[tex]P=2(x+y)[/tex]
[tex]P(4.80)=1,584[/tex]
[tex]P=330\ m[/tex]
so
[tex]330=2(x+y)[/tex] ----> equation A
[tex]x=4y-10[/tex] ------> equation B
substitute equation B in equation A and solve for y
[tex]330=2(4y-10+y)[/tex]
[tex]165=(5y-10)[/tex]
[tex]5y=165+10[/tex]
[tex]y=35[/tex]
Find the value of x
[tex]x=4(35)-10=130[/tex]
therefore
The length of the field is 130 meters and the width of the field is 35 meters
step 2
Find the area of the field
The area of the field is
[tex]A=xy[/tex]
substitute
[tex]A=(130)(35)=4,550\ m^2[/tex]
step 3
Find the number of bags of seed
Divide the area by 460
[tex]4,550/460=9.89\ bags[/tex]
Round up to the nearest whole number
[tex]9.89=10\ bags[/tex]
step 4
Find the cost of the seed
[tex](10)(3.98)=\$39.8[/tex]
step 5
Find the total money invested in the field
[tex]\$1,584+\$39.8=\$1,623.80[/tex]