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Task I
John has decided to fix up an old field for his son's horse. The length of the field is
10 meters less than 4 times its width. First, he fenced in the field at a cost of $4.80
per meter. The total cost was $1,584. He now needs to buy sweet grass seed to plant
in the field. The seed costs $3.98 per bag and covers 460 square meters.
How much money will John have invested in this field?​

Respuesta :

Answer:

The total money invested in the field will be [tex]\$1,623.80[/tex]

Step-by-step explanation:

step 1

Find the dimensions of the field

Let

x -----> the length of the field

y -----> the width of the field

we know that

The perimeter of the field is equal to

[tex]P=2(x+y)[/tex]

[tex]P(4.80)=1,584[/tex]

[tex]P=330\ m[/tex]

so

[tex]330=2(x+y)[/tex] ----> equation A

[tex]x=4y-10[/tex] ------> equation B

substitute equation B in equation A and solve for y

[tex]330=2(4y-10+y)[/tex]

[tex]165=(5y-10)[/tex]

[tex]5y=165+10[/tex]

[tex]y=35[/tex]

Find the value of x

[tex]x=4(35)-10=130[/tex]

therefore

The length of the field is 130 meters and the width of the field is 35 meters

step 2

Find the area of the field

The area of the field is

[tex]A=xy[/tex]

substitute

[tex]A=(130)(35)=4,550\ m^2[/tex]

step 3

Find the number of bags of seed

Divide the area by 460

[tex]4,550/460=9.89\ bags[/tex]

Round up to the nearest whole number

[tex]9.89=10\ bags[/tex]

step 4

Find the cost of the seed

[tex](10)(3.98)=\$39.8[/tex]

step 5

Find the total money invested in the field

[tex]\$1,584+\$39.8=\$1,623.80[/tex]

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