solve for x.
-px+r=-8x-2

Answer:
x = (2+r) / (p-8)
Step-by-step explanation:
-(px - r) = - (8x+2)
px-r = 8x+2
px-8x = 2+r
x(p-8) = 2+r
x = (2+r) / (p-8)
Considering x be the only variable. q and r be the constant in a linear system. Then the value of x is [tex]\rm \dfrac{r + 2 }{p-8}[/tex].
It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.
Given
The linear equation is [tex]\rm -px +r = -8x -2[/tex].
Let x be the only variable.
And q and r be the constant.
The value of x will be
[tex]\rm -px +r = -8x -2\\\\px - 8x \ = r + 2[/tex]
Take x common,
[tex]\rm x(p - 8) \ = r + 2[/tex]
Then divide it by p-8
[tex]\rm x = \dfrac{r + 2 }{p-8}[/tex]
Thus, the value of x is [tex]\rm \dfrac{r + 2 }{p-8}[/tex].
More about the linear system link is given below.
https://brainly.com/question/20379472