Which of the following statments must be true for a falling object that has been dropped from rest near the surface of earth.
An object falling near the surface of the earth has a constant acceleration of 9.8 m/s2. This means that the:A) object falls 9.8 m during the first second of its motion. B) object falls 9.8 m during each second of its motion. C) speed of the object increases by 9.8 m/s during each second of its motion. D)acceleration of the object increases by 9.8 m/s2 during each second of its motion. E)force of gravity on the object must be 9.8 N.

Respuesta :

Answer:

C) speed of the object increases by 9.8 m/s during each second of its motion.

Explanation:

Acceleration due to gravity is calculated by

[tex]ma=\frac{GMm}{R^2}\\\Rightarrow a=\frac{GM}{R^2}[/tex]

G = Gravitational constant = 6.67408 × 10⁻¹¹ m³/ kgs²

m = Mass of object

M = Mass of Earth = 5.972 × 10²⁴ kg

R = Radius of Earth = 6.371 × 10⁶ m

Plugging in the above values, we get

a = 9.8 m/s s

Acceleration due to gravity is denoted by 9.8 m/s² , this means that an object will change its velocity every second by 9.8.

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