solve for x.
d(-3+x)=kx+9

Answer:
x = -9 / (2d+k)
Step-by-step explanation:
d(-3x+x) = kx+9
-3dx + dx = kx+9
-3dx + dx - kx = 9
x(-3d+d-k) = 9
x (-2d-k)= 9
x [-(2d+k)]=9
x = -9 / (2d+k)
Answer:
The value of the provide equation for x is [tex]x=\frac{9+3d}{d-k}[/tex].
Step-by-step explanation:
Consider the provided equation.
[tex]d(-3+x)=kx+9[/tex]
We need to solve the equation for x.
Use the distributive property: [tex]a(b+c)=ab+ac[/tex]
[tex]-3d+xd=kx+9[/tex]
Subtract kx from both sides.
[tex]-3d+xd-kx=kx-kx+9[/tex]
[tex]-3d+xd-kx=9[/tex]
Add 3d both sides.
[tex]-3d+3d+xd-kx=9+3d[/tex]
[tex]xd-kx=9+3d[/tex]
Take x common from left side.
[tex]x(d-k)=9+3d[/tex]
Divide both the sides by d-k.
[tex]\frac{x(d-k)}{d-k}=\frac{9+3d}{d-k}[/tex]
[tex]x=\frac{9+3d}{d-k}[/tex]
Hence, the value of the provide equation for x is [tex]x=\frac{9+3d}{d-k}[/tex].