Question

The average weight of the top 5 fish at a fishing tournament was 12.3 pounds. Some of the weights of the fish are 12.8, 12.6, 11.8, 9.7. What was the weight of the heaviest fish?

Answer 1

Answer:

The weight of the heaviest fish was 14.6 pounds.

Step-by-step explanation:

We know that the mean is the sum of the values of all the observations over the number of observations, so we can set an equation and solve for the weight of the last fish:

(12.8+12.6+11.8+9.7+x)/5 = 12.3

46.9 + x = 61.5

x = 14.6

Since 14.6 more than all the other weights, the weight of the heaviest fish was 14.6 pounds.

Answer 2

Answer:

The weight of the heaviest fish is 27.1 pounds

Step-by-step explanation:

Weights of four fishes are 2.8, 12.6, 11.8, 9.7

Let the weight of fifth fish be x

Now we are given that The average weight of the top 5 fish at a fishing tournament was 12.3 pounds.

So, $Average = \frac{\text{Sum of all weights}}{\text{No. of fishes }}$

$12.8= \frac{2.8+12.6+11.8+9.7+x}{5}$

$12.8= \frac{36.9+x}{5}$

$12.8 \times 5= 36.9+x$

$64= 36.9+x$

$64-36.9=x$

$27.1=x$

Hence The weight of the heaviest fish is 27.1 pounds