Respuesta :

Answer:

It is valid in the interval [tex][\frac{-\pi }{2},\frac{+\pi }{2}][/tex]

Step-by-step explanation:

Let [tex]f(x)=sin^{-1}(sin(x))[/tex]

The domain of the given function is

[tex]sin(x)\in [-1,1]\\\\(\because sin^{-1}x[/tex]is defined only for x in the set[-1,+1])

Thus we have

[tex]-1\leq sin(x)\leq +1\\\\\Rightarrow sin^{-1}(-1)\leq sin^{-1}(sin(x))\leq sin^{-1}1\\\\\therefore \frac{-\pi }{2}\leq sin^{-1}(sin(x))\leq \frac{+\pi }{2}\\[/tex]

[tex]\therefore x\in [-\pi /2,+\pi /2][/tex]

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