Answer:
It is valid in the interval [tex][\frac{-\pi }{2},\frac{+\pi }{2}][/tex]
Step-by-step explanation:
Let [tex]f(x)=sin^{-1}(sin(x))[/tex]
The domain of the given function is
[tex]sin(x)\in [-1,1]\\\\(\because sin^{-1}x[/tex]is defined only for x in the set[-1,+1])
Thus we have
[tex]-1\leq sin(x)\leq +1\\\\\Rightarrow sin^{-1}(-1)\leq sin^{-1}(sin(x))\leq sin^{-1}1\\\\\therefore \frac{-\pi }{2}\leq sin^{-1}(sin(x))\leq \frac{+\pi }{2}\\[/tex]
[tex]\therefore x\in [-\pi /2,+\pi /2][/tex]