Answer:
The correct answer is 0.015 meters.
Explanation:
We know that the change in length of a material on account of temperature change is given by
[tex]\Delta L=L_{o}\alpha \Delta T[/tex]
where
[tex]L_{o}[/tex] is the initial Length
[tex]\alpha [/tex] is the coefficient of linear thermal expansion
[tex]\Delta T[/tex] is the change in temperature.
Applying values we get
[tex]\Delta L=50\times 12\times 10^{-6} \times 25\\\\\therefore \Delta L=0.015meters[/tex]