Respuesta :
Answer: B. [tex]65.3\pm(2)(0.3)[/tex]
Step-by-step explanation:
The confidence interval for the population mean is given by :-
[tex]\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}[/tex]
Given : Sample size : n= 100
Sample mean : [tex]\overline{x}=65.3\text{ inches}[/tex]
Standard deviation: [tex]\sigma=3 \text{ inches}[/tex]
Level of confidence = 0.95
Significance level : [tex]\alpha=1-0.95=0.05[/tex]
Critical value : [tex]z_{\alpha/2}=1.96[/tex]
Then, 95% confidence interval for the population mean will be :-
[tex]65.3\pm (1.96)\dfrac{3}{\sqrt{100}}\\\\\approx65.3\pm(2)(\dfrac{3}{10})=65.3\pm(2)(0.3)[/tex]
Answer:
The answer for this Question is B.
Step-by-step explanation: