The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviation of two hours. If each time was increased by one hour, what would be the new mean and standard deviation? (2 points)

Respuesta :

aachen

Answer:

4.5 hour and 2 hour

Step-by-step explanation:

Given: The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviation of two hours.

To Find: If each time was increased by one hour, what would be the new mean and standard deviation.

Solution:

let the total numbers entries of hours in survey be   =   [tex]\text{N}[/tex]

each entry in survey be  =  [tex]\text{x}_{i}[/tex]

mean of survey is     =     [tex]\mu[/tex]  =[tex]3.5[/tex] [tex]\text{hours}[/tex]

standard deviation is  =   [tex]\sigma[/tex] = [tex]2[/tex] [tex]\text{hours}[/tex]

if each entry in survey is increased by one hour then,

each new entry in survey  is =  [tex]\text{x}_{i}+1[/tex]

the new mean is[tex]\mu_{new}[/tex]  = [tex]\frac{\text{sum of all hours}}{total number of entries}[/tex]

                                                [tex]\frac{\text{x}_{1} +1+\text{x}_{2}+1 +....+\text{x}_{N}+1 }{N}[/tex]

                                                [tex]\frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})+\text{N}\times1 }{N}[/tex]

                                                [tex]\frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})}{N}[/tex]+[tex]\frac{\text{N}\times1 }{N}[/tex]

                                             [tex]\mu_{new}[/tex] = [tex]\mu[/tex] + 1=[tex]4.5[/tex] [tex]\text{hours}[/tex]

now,

standard deviation is      [tex]\sigma_{new}=[/tex] [tex]\sqrt{\sum_{1}^{N}\frac{(\text{x}_{inew}-\mu_{new})^{2}}{N}}[/tex]

                                   [tex]\text{x}_{inew}= \text{x}_{i}+1[/tex]

                                   [tex]\mu_{new}=\mu+1[/tex]        

putting values,

                                                [tex]\sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}+1-\mu-1)^{2}}{N}}[/tex]

                                                [tex]\sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}-\mu)^{2}}{N}}[/tex]= [tex]\sigma[/tex]

                                 [tex]\sigma_{new}[/tex]        =2

new mean and standard deviation are [tex]4.5[/tex] and [tex]2[/tex] [tex]\text{hours}[/tex]

                                               

fichoh

The new mean and standard deviation of hours per day spent watching television are :

  • Mean = 4.5 hours
  • Standard deviation = 2 hours

When a constant value is added to all values in a dataset :

  • The value of Standard deviation remains unchanged
  • The value of the mean increases by the same amount or value added to each value.
  • New mean = initial mean + 1 = 3.5 + 1 = 4.5
  • New standard deviation = initial standard deviation = 2

Therefore, the new mean and standard deviation are 4.5 hours and 2 hours respectively.

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