Answer:
Let a = admission fee
Let n = number of people who attended the party
(1) If the admission fee had been $0.75 less and 100 more people attended, the club would have received the same amount in admission fees.
[tex]an=(a -0.75)(n+100)[/tex]
[tex]an =an-0.75n+100a-75[/tex]
[tex]0.75n-100a =-75[/tex] ...(1)
(2) If the admission fee had been $1.50 more and 100 fewer people had attended, the club would have received the same amount in admission fees.
[tex]an=(a+1.50)(n-100)[/tex]
[tex]an= an+1.5n-100a-150[/tex]
[tex]1.5n-100a= 150[/tex] ......(2)
Subtracting (1) from (2) we get
[tex]0.75n=225[/tex]
n = 300
And substituting n = 300 to get value of a;
[tex]1.5(300)-100a= 150[/tex]
[tex]450-100a=150[/tex][tex]-100a=-450+150[/tex]
[tex]100a=300[/tex]
a = 3
Hence, $3 was admission fee and 300 people attended the party.