Answer:
(-∞, ∞)
Step-by-step explanation:
Let's solve each inequality separately.
[tex]\begin{array}{rcl}3(2x + 1) & > & 21\\2x+1 & > & 7\\2x & > & 6\\x & > & 3\\\end{array}[/tex]
[tex]\begin{array}{rcl}4x + 3& < & 3x + 7\\x + 3 & < & 7\\x & < & 4\\\end{array}[/tex]
The solution is x > 3 or x < 4
Since x could be less than 4 or greater than 3, x could be any number.
The best interpretation for the solution set is (-∞, ∞).
