Question

A sample of gas with a mass of 8.40 g occupies a volume of 4.50 L at 298 K and 1.10 atm. What is the molar mass of the gas?

Answer 1

Answer:

41.5225 g/mol

Explanation:

Given that:

Pressure = 1.10 atm

Temperature = 298 K

Volume = 4.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1.10 atm × 4.50 L = n × 0.0821 L.atm/K.mol × 298 K  

⇒n = 0.2023 moles

Given that : Amount = 8.40 g

Molar mass = ?

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.2023= \frac{8.40\ g}{Molar\ mass}$

$Molar\ mass= 41.5225\ g/mol$