Ali pushes a toy car initially at rest towards javed by exerting a constant horizontal force F of magnitude 10N through a distance of 2 meters. How much work is done onthe toy car? a 5j b) 10j c) 15j d) 20j e) 25j

Respuesta :

Answer: d) 20J

Explanation:

Work [tex]W[/tex] done by a Force [tex]F[/tex] refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  

It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:  

[tex]1J=(1N)(1m)=Nm[/tex]  

Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:

 

[tex]W=(F)(d)[/tex] (1)

When they are not parallel, both directions form an angle, let's call it [tex]\alpha[/tex]. In that case the expression to calculate the Work is:  

[tex]W=Fdcos{\alpha}[/tex] (2)

In this case both (the force and the distance in the path) are parallel, so the work [tex]W[/tex] performed is the product of the force [tex]F[/tex] by the distance traveled [tex]d[/tex]. as shown in equation (1).

Hence:

[tex]W=(10N)(2m)[/tex]  

[tex]W=20Nm=20J[/tex] >>>>This is the work

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