For sin2x+cosx=0, use a double-angle or half-angle formula to simplify the equation and then find all solutions of the equation in the interval [0,2π).

Respuesta :

Answer:

Step-by-step explanation:

Given is a trignometric equation in x, as

[tex]sin2x+cosx=0[/tex]

TO make it in one trig ratio, we can replace sin2x as 2sinx cosx

WE get now

[tex]2sinxcosx+cosx=0\\[/tex]

[tex]cosx(2sinx+1)=0\\cosx=0, sinx =-0.5\\[/tex]

Principal solution is [tex]x=\frac{\pi}{2} , \frac{-\pi}{6}[/tex]

x = ±π/2 + 2kπ, where k is any integer or

x=±pi/6 +k pi, where k is any integer.

General solution is

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