Answer:
Step-by-step explanation:
Let X be the sample who exercise regularly and Y who do not
X Y X-Y
70 72 -2
63 78 -15
63 69 -6
66 74 -8
73 74 -1
70 72 -2
63 78 -15
Mean -7
Var 36
std dev 6
Let us create hypotheses as:
[tex]H_0: x bar - y bar =0\\H_a: x bar -y bar <0[/tex]
(One tailed test)
Test statistic = mean diff/std error = [tex]\frac{-7}{\frac{6}{\sqrt{6} } } \\[/tex]
=-2.86
df = n1+n2-2 = 14
p = 0.006299
SInce p <0.05, reject null hypothesis
There is statistical evidence to show that heart beats are lower for persons who exercise.