Question

Find the length of AB to the nearest hundredth

Answer 1

Answer:  The required length of AB is 7.28 units.

Step-by-step explanation:  We are given to find the length of line segment AB to the nearest hundredth.

From the graph, we note that the co-ordinates of point A are (-5, -4) and co-ordinates of B are (-3, 3).

We know that the length of AB is the distance between the points A and B.

DISTANCE FORMULA :  The distance between the points (a, b) and (c, d) is given by

$D=\sqrt{(c-a)^2+(d-b)^2}.$

The distance between the points A(-5, -4) and B(-3, 3) is given by

$D=\sqrt{(-3+5)^2+(3+4)^2}=\sqrt{4+49}=\sqrt{53}=7.2801.$

Rounding to nearest hundredth, we get

D = 7.28 units.

Thus, the required length of AB is 7.28 units.

Answer 2

AB = 7.28 units

Solving this question will entail making use of distance formula where we find the distance of a line between two coordinates.

The formula is;

AB = $\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$

Where;

(x₁, y₁) is coordinate of point A

(x₂, y₂) is coordinate of point B

From the graph, we can see that;

(x₁, y₁) = (-5, -4)

(x₂, y₂) = (-3, 3)

Thus;

AB = $\sqrt{(-3 - (-5))^{2} + (3 - (-4))^{2}}$

AB = $\sqrt{4 + 49}$

AB = $\sqrt{53}$

AB = 7.2801

To the nearest tenth gives;

AB = 7.28 units

Read more at; brainly.com/question/17204526