Answer:
A
Step-by-step explanation:
Given a parabola in standard form : y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]
y = 2x² + 16x + 33 ← is in standard form
with a = 2 and b = 16, thus
[tex]x_{vertex}[/tex] = - [tex]\frac{16}{4}[/tex] = - 4
Substitute x = - 4 into the equation for the corresponding value of y
y = 2(- 4)² + 16(- 4) + 33 = 32 - 64 + 33 = 1
vertex = (- 4, 1 )
To find the y- intercept let x = 0 in the equation
y = 2(0)² + 16(0) + 33 = 0 + 0 + 33 = 33
y- intercept = (0, 33 )
