Answer:
The side length of the original cube is 5.43 ft
Step-by-step explanation:
Let x be the edge ( in feet ) of the cube,
∵ Volume of a cube = side³,
Thus, the volume of the given cube,
[tex]V=x^3[/tex]
Now, 4ft thick slice is cut off the top of a cube,
The volume of the slice = x × x × 4 = 4x² ft²,
Thus, the volume of the resulting figure = volume of cube - volume of cut figure
= ( x³ - 4x² ) ft²
According to the question,
[tex]x^3-4x^2=42[/tex]
[tex]\implies x^3-4x^2-42=0[/tex]
The solution of the above equation will be obtained by finding the zeros of the function [tex]f(x)=x^3-4x^2-42[/tex] ( by graphing ),
We found that,
The graph of the equation intersect x at (5.426,0)
Thus, the zero of the equation is 5.426
⇒ x = 5.426 ≈ 5.43
Hence, the side length of the original cube is 5.43 ft ( approx )