In the figure, PA and PB are tangent to circle O and PD bisects BPA. The figure is not drawn to scale.

Answer:
48
Step-by-step explanation:
Since PD bisects BPA, we can say angle AOC and BOC are equal. So Angle BOC = 42.
Since PB is tangent to the circle, PBO is 90 degrees (tangent means 90 degrees at point of tangency).
Now looking at triangle PBO (also, 3 angles of a triangle add up to 180), we can say:
BPO + PBO + BOC = 180
BPO + 90 + 42 = 180
BPO + 132 = 180
BPO = 180 - 32 = 48
Option c is right.