Question

How do you figure out 1/2(8x+4)-1/3(3x+9)=17

Answer 1

The most basic approach here is to simplify as much as possible. Therefore you do:
(1/2 x 8x + 1/2 x 4) - (1/3 x 3x + 1/3 x 9) =17
(4x + 2) - (x + 3) = 17
4x + 2 - x - 3 = 17
3x - 1 = 17
Then you pass the one on the other side which gives:
3x = 17 + 1
3x = 18
Finally divide everything by 3:
x = 6

Answer 2

Answer:

x = 6

Step-by-step explanation:

1/2(8x+4)-1/3(3x+9)=17 can be calculated as:

Firstly, simplify 1/2(8x+4) to become (1*8x+4)/2 = (8x+4)/2

Secondly, factor out the common term 4:

(8x+4)/2 = 4(2x+1)/2

Now we got the equation:

4(2x+1)/2  -  1/3(3x+9)=17

After this, we see that 4(2x+1)/2 can be simplify to:

2(2x+1)

Thirdly, simplify 1/3(3x+9) = 1*(3x+9)/ 3 = (3x+9) / 3

Factor out the common term 3:

= 3(x+3)/3

Now we got the equation:

2(2x+1) - 3(x+3)/3 = 17

Cancel 3, we got:

2(2x+1) - (x+3) = 17

Break the brackets:

4x+2 - x - 3 = 17

4x - x - 3 + 2 = 17

3x - 1 = 17

Add 1 to both side:

3x - 1 + 1 = 17 + 1

3x - 0 = 18

3x = 18

Divide both side by 3:

3x /3 = 18/3

1x = 6

x = 6

Hope this help you :3